Radioactive Decay And Acid Dissociation Constant Chap. 9 And 10 Worksheet With Answers - Middle Tennessee State University Page 8
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202 -
+
3 -
+
-
-
+
2 -
HAsO
H
+ AsO
2) H
AsO
H
+ HAsO
1) H
AsO
H
+H
AsO
3)
3
4
2
4
2
4
4
4
4
-
H
AsO
is the strongest acid; H
AsO
is the weakest base.
3
4
2
4
3 -
2 -
AsO
is the weakest acid;
, is the strongest base.
HAsO
4
4
Analysis of Acids and Bases (Section 9.10)
9.89 Describe the difference between the information obtained by measuring the pH
of an acid solution and by titrating the solution, using and indicator, with base.
Solution
+
The pH of a solution measures the [H
] actually present in the solution at that
+
instant. The titration determines the total amount of [H
] ultimately available
from the acid for reaction with the base.
9.91 Determine the number of moles of NaOH that could be neutralized by each of
the following:
a) 1.00 L of 0.200 M HCl
b) 500 mL of 0.150 M HNO
3
Solution
0.200 mol HCl
1mol NaOH
1.00 L soln x
x
= 0.200 mol NaOH
a)
1L soln
1mol HCl
0.150 mol HNO
1mol NaOH = 0.0750 mol NaOH
3
0.500 L soln x
x
1L soln
1molHNO
b)
3
Titration Calculations (Section 9.11)
9.95 Write a balanced molecular equation to represent the neutralization reaction
between HCl and each of the following bases:
a) Cd(OH)
b) Cr(OH)
c) Fe(OH)
2
3
2
Solution
+ 2HCl CdCl
+ 3HCl CrCl
a) Cd(OH)
+ 2H
O
b) Cr(OH)
+ 3H
O
2
2
2
3
3
2
+ 2HCl FeCl
c) Fe(OH)
+ 2H
O
2
2
2
9.97 A 25.00 mL sample of gastric juice is titrated with 0.0210 M NaOH solution. The
titration to the equivalence point requires 29.8 mL of NaOH solution. If the
equation for the reaction is HCl(aq) + NaOH(aq) NaCl(aq) + H
O(l)
2
what is the molarity of HCl in the gastric juice?
Solution
1L
0.0210molNaOH
1molHCl =6.26 x10
- 4
moles HCl =29.8mL x
x
x
molHCl
1000 ml
1L
1molNaOH
- 4
1000 mL
6.26X10
molHCl x
MofHCl =
=0.0250MHCl
1L
25.00 mL
9.99 A 20.00 mL sample of each of the following acid solution is to be titrated to the
equivalence point using 0.120 M NaOH solution. Determine the milliliters of
NaOH solution that will be needed for each acid sample.
a) 0.180 M HCl
b) 0.180 M H
SO
2
4
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