Using The Born Haber Cycle To Determine H For An Ionic Compound

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Using The Born Haber cycle to determine ∆H for an ionic compound
Values you need to “look up” are on your Heat of formation chart (∆H
° chart) and the back of
f
your VSEPR chart.
Na(s) + 1/2 Cl
(g) –––> NaCl(s)
2
Step 1: Make gaseous atoms from “standard state” elements. Both processes are Endothermic
(Breaking bonds always absorbs energy)
Na(s) –––> Na(g)
∆H = ∆H
° for Na(g) = + 108 kJ
f
1/2 Cl
(g) –––> Cl(g)
∆H = ∆H
° for Cl(g) = + 122 kJ
2
f
(you could also use Bond energy for Cl
. Break 1/2 mol of Cl–Cl bonds = 242 kJ/2
2
= + 121 kJ or basically same energy)
Step 2: Make gaseous ions and transfer the electrons
Na loses an electron:
1st ionization energy
(Na absorbs energy to remove an electron,
Na(g) –––> Na
+
(g) + e
∆H = +496 kJ
Endothermic)
Cl gains an electron:
Electron affinity
(Cl releases energy to add an electron,
Cl(g) + e
–––> Cl
(g)
∆H = –349 kJ
Exothermic)
Step 3: Bring gaseous ions together to make an ionic solid = Lattice energy.
Na
+
(g) + Cl
(g) –––> NaCl(s)
∆H = – 788 kJ
Lattice energy is the energy required to separate 1 mol of an ionic compound into gaseous ions.
The value is +, endothermic, to separate the ions (add energy to break bonds) or
–, exothermic, to bring the ions together (release energy when bonds are made)
When a compound is made, the ions are coming together, so the negative lattice energy is the last
step in the Born- Haber process. The large amount of energy released as the ions come together is
the factor that makes the formation of stable ionic compounds Exothermic.
To get overall ∆H, add up ∆H for each step, or Hess’s Law.
+108 + 122 + 496 – 349 – 788 kJ = –411 kJ which is very close to ∆H
° for NaCl(s)
f
Exothermic (∆H = – 411 kJ) so the compound is stable (you would have to add energy to break up
the compound).

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