Some Review Problems For Exam 1 Chem 1a Page 3
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1
2
3b. How many molecules of H
will be produced from this reaction? (Starting with
2
0.500 g Al)
27.
Fe
+
H
O
Fe
O
+
H
→
(s)
2
(g)
3
4 (s)
2 (g)
If 50.0 g iron and 30.0 g water are combined,
a. What mass of iron oxide will be formed in theory?
c. What mass of the excess reactant will be left over?
d. If the actual yield of iron oxide is 60.2 g, calculate the percent yield of this
reaction.
Answers:
1a.
7.5 mol
13.
ef = C
H
N, mf = C
H
N
2
6
4
12
2
1b.
0.00137 mol
15.
a. 24 g H
SO
2
4
1c.
0.820 g
b. 53.2 mL solution
2
3
1d.
1.7 × 10
cm
c. 0.974 M Na
SO
2
4
16
a. Mn is ox, O is red.
2.
29.73 % Fe
b. Cr is red., Cl is ox.
19.18 % C
17.
a. will react, b. won’t, c. will
51.10 % O
react (see answers for reactions.)
3.
2Al + 3F
→ 2AlF
2
3
18.
Using wt. ave mass of 107.8682
4a.
19.0 g
from the per. table in the text, abundance
4b.
44.6 kg
107
109
of
Ag = 51.835% and
Ag =
4c.
13.7 g
85
48.165%
5.
Rb is more abundant
14
19, 20: see answers
6.
2.0 × 10
atoms
-
0
21.
47 protons, 47 e
, 62 n
7.
C
H
O
9
10
2
22, 23, 24: see answers
8a.
Al(OH)
+ 3 HCl → 3 H
O +
3
2
3
25.
27.1 in
AlCl
3
26a.
4.50 g HBr
8b.
3.46 g
22
26b.
1.67×10
H
molecules
8c.
0.99 g left
2
27a.
69.1 g Fe
O
9.
154 g CO
, 71.0 g H
O
3
4
2
2
27b.
8.5 g water left
20
3
10.
4.04 × 10
molecules/in
27c.
87.1 % yield
11.
28.09 amu
12.
see separate sheet of answers
3
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