Chemical Calculations Worksheet Page 2
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1
2Identify the limiting and excess reactants.
4. Sulfur reacts with oxygen gas to produce sulfur trioxide gas.
(g) → 2SO
Balanced Equation:
2S(s) + 3O
(g)
2
3
If 6.3 g of sulfur reacts with 10.0 g of oxygen gas, what is the limiting reactant?
How many grams of sulfur trioxide will be produced?
(I added an extra digit to the 6.3 g of sulfur to even up the sig figs)
1 mol S
2 mol SO
80.07 g SO
6.30 g S ×
×
3
×
3
= 15.7 g SO
possible from S
3
32.07 g S
2 mol S
1 mol SO
3
1 mol O
2 mol SO
80.07 g SO
×
2
×
3
×
3
10.0 g O
= 16.7 g SO
possible from O
2
3
2
32.00 g O
3 mol O
1 mol SO
2
2
3
So, the sulfur is the LR and O
is in excess, with 15.7 g of SO
as the theoretical yield.
2
3
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