Acids And Bases Review Sheet Page 2
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1
2Total = ______________
Solve the following acid-base problems.
26. What is the hydrogen ion concentration in a wheat flour and water solution if [OH
] = 1.0 x 10
M? Is the wheat
-
-8
flour and water acidic, basic or neutral?
pOH = 8, pH = 6, [H
] = 1 x 10
M, ACIDIC
+
-6
27. What is the pH of peaches if the [OH
] = 3.16 x 10
M? Are peaches acidic, basic, or neutral?
-
-11
pOH = 10.5, pH = 3.5, ACIDIC
28. What is the [H
+
] concentration in eggs if [OH
] = 6.0 x 10
M? Are eggs acidic, basic, or neutral?
-
-7
pOH = 6.22, pH = 7.78, [H
] = 1.6 x 10
M, BASIC
+
-8
29. An aqueous solution contains a 0.0361 M OH
concentration. Calculate the pOH, pH and [H
+
]. Determine if the
-
solution is acidic or basic.
pOH = 1.44, pH = 12.56, [H
] = 2.75 x 10
M, BASIC
+
-13
+
30. Lake Ontario has water with an [H
] of approximately 1.1 x 10
M. Determine whether the water is slightly
-6
acidic or slightly basic.
pH = 5.96. ACIDIC
31. If the pH of a diet soda is 3.21 at 25°C, what are the hydrogen ion and hydroxide ion concentrations in the
soda?
[H
] = 6.17 x 10
, [OH
] = 1.62 x 10
M
+
-4
-
-11
32. Most fish species die in water with a [H
+
] of between 3.16 x 10
M and 1.0 x 10
M. What is the pH range
-5
-5
where most fish species die? What are the corresponding [OH
] values for fish death?
-
pH = 4.5 – 5. pOH = 9 – 9.5, [OH
] = 1 x 10
– 1 x 10
(or 3.16 x 10
)
-
-9
-9.5
-10
Solve the following titration problems.
33. A) Write the balanced chemical equation of the neutralization reaction between sodium hydroxide and sulfuric
acid.
2NaOH + H
SO
2H
O + Na
SO
2
4
2
2
4
B) How many moles of sodium hydroxide are needed to neutralize 0.35 mol of sulfuric acid?
0.7 moles
C) How many mL of a 0.20 M sodium hydroxide solution is needed to neutralize 75 mL of a 0.45 M sulfuric
acid solution?
75 mL of 0.45 M = 0.03375 mol H
SO
. 0.03375 x 2 = 0.0675 mol NaOH. 337.5 mL
2
4
D) How many mL of a 1.5 M sulfuric acid solution is needed to neutralize 55 mL of a 0.75 M sodium hydroxide
solution?
55 mL of 0.75 M = 0.04125 mol NaOH. 0.04125 / 2 = 0.020625 mol H
SO
. 13.75 mL
2
4
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