Kinetics & Equilibrium Chemical Reactions Worksheet With Answer Key Page 8

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4)
5)
(a) As volume decreases, pressure increases and the reaction shifts in the direction of fewer
molecules (less volume; more SO
) to relieve the stress. Value of K
does not change.
3
eq
(b) Additional O
disturbs the equilibrium and SO
is formed to relieve the stress. Value of K
2
3
eq
does not change.
(c) Increase in temperature shifts the reaction to the left to “use up” some of the added heat.
Less SO
remains. Value of K
decreases due to the relative greater increase in the rate
3
eq
of the endothermic reaction (reaction to the left).
6)
(a) CO will decrease. An increase of hydrogen gas molecule will increase the rate of the
reverse reaction which consumes CO. A LeChatelier Principle shift to the left.
(b) CO will increase. Since the forward reaction is endothermic (a H > 0) an increase in
temperature will cause the forward reaction to increase its rate and produce more CO. A
LeChatelier Principle shift to the right.
(c) CO will decrease. A decrease in volume will result in an increase in pressure, the
equilibrium will shift to the side with fewer gas molecules to decrease the pressure, , a
shift to the left.
(d) CO will remain the same. Once at equilibrium, the size of the solid will affect neither the
reaction rates nor the equilibrium nor the concentrations of reactants or products.

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