EQT 272 PROBABILITY AND STATISTICS
SEMESTER 1
2012/2013
4
1
P
( A
)
8
2
B = defective calculator 2,
1M
= { D
D
D
, D
D
A
, A
D
D
, A
D
A
}
1A
1
2
3
1
2
3
1
2
3
1
2
3
4
1
P
(B
)
8
2
A ∩ B = defective calculator 1 and 2
1M
= { D
D
D
, D
D
A
}
1
2
3
1
2
3
1A
2
1
P
(
A
B
)
8
4
B
C = all defective calculator 2, all defective calculator 3
= { D
D
D
, D
D
A
, A
D
D
, A
D
A
, D
A
D
, A
A
D
}
1
2
3
1
2
3
1
2
3
1
2
3
1
2
3
1
2
3
1M
6
3
1A
P
(
B
C
)
8
4
8Marks