Solubility Curve Problems Chemistry Paper (Page 2 of 2) in pdf

Solubility Curve Problems Chemistry Paper Page 2

1. As temperature increases both the speed of the water molecules and the

number of collisions increase. A solid remains dissolved by the continual

motion of the water molecules. The more energy and motion, the more

particles that can remain in solution. This is especially true for ionic

compounds, which are polar because water is polar and the opposite

charges help to stick the water molecules to the ions. Gasses are often non-

polar, and they have very low boiling points, so as temperature increases

they tend to "boil away". That is why a soda will go flat much faster if it is

left in a warm place.

2. NaNO 3 because the higher line indicates that more NaNO 3 can be

dissolved.

3. The line marks the saturation point of a solute in 100 grams of water. If

you have less grams dissolved than indicated by the line then your solution

is unsaturated. If you have more, then your solution is supersaturated.

4. 70g

5. 70g/2 = 35g

6. 10g x 3 = 30g

7. The graph indicates that 104 grams of KNO 3 will dissolve in 100 grams of

water, so I only need 104/2 = 52 grams of KNO 3 to make my solution. So, I

would measure out 50 grams of water and 52 grams of KNO 3 and mix

them together to make the solution.

8. You would need to know the temperature of the solution. The saturation

point is very different depending on the temperature.

9. 100 grams of water at 10°C can hold 70grams of NH 3 .

100 grams of water at 80°C can hold 14 grams.

So 70 - 14 = 56 grams of NH3 would bubble out.

10. From the graph 100 grams of water at 50°C can hold 80 grams of HNO 3 .

So, 400 grams can hold 80g x 4 = 320 grams of HNO 3 .

From the graph 100 grams of water at 10°C can hold 20 grams of HNO 3 .

So, 400 grams can hold 20g x 4 = 80 grams of HNO 3 .

As the solution is cooled 320 - 80 = 240 grams of HNO 3 will form crystals.

Solubility Curve Problems Chemistry Paper Page 2