Molecular Orbital Theory, Valence Bond Theory And Hybridization Worksheets (Page 2 of 8) in pdf

Molecular Orbital Theory, Valence Bond Theory And Hybridization Worksheets Page 2

Chemistry 121 Problem set VI solutions - 2

e) Nonpolar. ∆EN (O-C) = 1. The 2 opposing ∆EN (O-C) vectors cancel.

a) Lewis structure is first structure and has an extra lone pair on the central atom

b) VSEPR

5 bp + 1 lp = 6

shape is octahedral

c) Molecular shape is square pyramid (second structure).

d) Hybridization is sp

(VSEPR 6 pairs on central atom so need 6 orbitals)

e) Weakly polar. ∆EN (F-I) = 1.5. The 4 ∆EN (F-I) vectors in the square plane will cancel. The ∆EN (F-I)

vector will come close to cancelling with the lone pair vector.

a) Lewis structure is first structure and has an extra lone pair on the central atom

b) VSEPR

4 bp + 1 lp = 5

shape is trigonal bipyramidal

c) Molecular shape is seesaw (second structure).

d) Hybridization is sp

d (VSEPR 5 pairs on central atom so need 5 orbitals)

e) Weakly polar. ∆EN (F-S) = 1.5. The 2 ∆EN (F-S) vectors in the vertical plane will cancel. The resultant

of the two ∆EN(F-S) vectors will come close to cancelling with the lone pair vector in the horizontal

triangular plane.

ICl

a) Lewis structure is first structure and has two extra lone pairs on the central atom

b) VSEPR

3 bp + 2 lp = 5

shape is trigonal bipyramidal

c) Molecular shape is T shaped (second structure).

d) Hybridization is sp

d (VSEPR 5 pairs on central atom so need 5 orbitals)

e) Polar. ∆EN (Cl-I) = 0.5. The 2 ∆EN (F-S) vectors in the vertical plane will cancel. The resultant of the

two lone pair vectors will be much greater than the ∆EN (F-S) vector in the horizontal triangular plane.

XeF

a) Lewis structure is first structure and has three extra lone pairs on the central atom

b) VSEPR

2 bp + 3 lp = 5

shape is trigonal bipyramidal

c) Molecular shape is linear, lone pairs go into the horizintal trigonal plane. (second structure).

d) Hybridization is sp

d (VSEPR 5 pairs on central atom so need 5 orbitals)

e) Nonpolar. ∆EN (F-Xe) = 1.4. The 2 ∆EN (F-Xe) vectors in the vertical plane will cancel. The 3 lone pair

vectors in the horizontal triangular plane will cancel.

Molecular Orbital Theory, Valence Bond Theory And Hybridization Worksheets Page 2