Ratios And Rates Worksheet - Chapter 3 Page 14

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Reflecting
Why do you get an equivalent ratio when you multiply the
A.
numbers in one column by the same amount?
B.
Why did Preston get an equivalent ratio when he added the
column with 20 and 30 and the column with 8 and 12?
What other ratio table could you have used to solve the same
C.
problem?
WORK WITH
the Math
Example 2
Solving a proportion using a ratio table
6
2
0
Solve
using a ratio table.
9
0
Allison’s Solution
2
0
I started the table with the ratio I knew,
.
9
0
x 3
÷ 10
I wanted a first term of 6.
I noticed that 20 and 90 had a common factor of 10, so I divided
20
2
6
them by 10 to get an equivalent ratio in lower terms.
90
9
27
Then I multiplied 2 by 3 to get 6.
÷ 10
x 3
I multiplied 9 by 3, since both terms must be multiplied by the
same number.
6
2
0
=
2
7
9
0
The missing term is 27.
Brian’s Solution
I started the table with the ratio in which I knew both terms.
÷ 10
x 2
I wanted a first term of 6.
Doubling is easy to do, so I did that. I realized that the
20
40
60
6
sums of the first two columns would give 60 as the first
90
180
270
27
term and 270 as the second.
+
÷ 10
I divided by 10 to get 6 as the first term.
6
2
0
=
2
7
9
0
The missing term is 27.
115
Ratios and Rates
NEL

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