Ratios And Rates Worksheet - Chapter 3 Page 8
ADVERTISEMENT
1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27
28
29
30
31
32
33
34
35
36
37
38Example 3
Solving a ratio problem using a proportion
The ratio of the mass of oats to barley in some horse feed is 4 : 11.
How many kilograms of each grain are in 150 kg of feed?
Aaron’s Solution
I represented the ratio with a diagram. I represented
O O O O B B B B B B B B B B B
oats with O and barley with B.
4 parts
11 parts
4 :11 is a part-to-part ratio. I added the parts to
The whole is 15.
determine the whole.
4
I wrote fractions to describe what part of 15 kg of feed
Oats =
of total mass
1
5
is oats and what part is barley.
1
1
Barley =
of total mass
1
5
To find out the amount of oats in 150 kg of feed,
4
=
Oats :
4
15
150
I needed an equivalent fraction for
with a
1
5
x 10
denominator of 150.
x 10
I multiplied the denominator by 10, so I had to multiply
4
40
the numerator by 10.
=
15
150
x 10
Mass of oats = 40 kg
I subtracted to figure out how much of the mass is
Mass of barley = 150 – 40
barley.
= 110
In 150 kg of feed, there are 40 kg of
oats and 110 kg of barley.
Misa’s Solution
I figured that if there were 4 kg of oats and 11 kg of
4 + 11 = 15
barley, there would be 15 kg of feed.
I realized that 150 is 10 times as much as 15, so the
150 ÷ 15 = 10
parts would also have to be 10 times as much.
4 x 10 = 40 kg oats
11 x 10 = 110 kg barley
109
Ratios and Rates
NEL
ADVERTISEMENT
0 votes
Related Articles
Related forms
Related Categories
Parent category: Education