Chemistry Worksheets - Chem 340, Fall 2013 Page 10
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19P5.19) Under anaerobic conditions, glucose is broken down in muscle tissue to form
2CH
lactic acid according to the reaction C
H
O
CHOHCOOH. Thermodynamic
6
12
6
3
data at T = 298 K for glucose and lactic acid are given here:
–1
–1
1
1
1
S°(J K
mol
)
f
p
–1273.1
Glucose
219.2
209.2
–673.6
Lactic acid
127.6
192.1
Calculate the entropy of the system, the surroundings, and the universe at T = 310. K.
Assume the heat capacities are constant between T = 298 K and T = 330. K.
= C
o
o
The standard entropy and enthalpy and heat capacity for this reaction are:
note: here C
P
rxn
p
ΔS
ν
-1
1
-1
1
-1
-1
(
298
K
)
S
2
1
92.1
J
K
mol
1
2
09.2
J
K
mol
175
0 .
J
K
mol
reaction
i
i f,
i
ΔH
ν
1
1
-1
(
298
K
)
H
2
673
6 .
kJ
mol
1
1273
1 .
kJ
mol
74
1 .
kJ
mol
reaction
i
i f,
i
-1
1
-1
1
-1
-1
C
(
298
K
)
2
1
27.6
J
K
mol
1
2
19.2
J
K
mol
36
0 .
J
K
mol
p,
reaction
At 310 K the entropy and enthalpy for this reaction are then:
T
ΔS
ΔS
f
(
310
K
)
(
298
K
)
C
ln
reaction
reaction
p,
reaction
T
i
310
K
1 -
1 -
1 -
1 -
1 -
1 -
175
0 .
J
K
mol
3
6.0
J
K
mol
ln
176
4 .
J
K
mol
298
.
15
K
ΔH
ΔH
(
310
K
)
(
298
K
)
C
T
T
reaction
reaction
reaction
f
i
1 -
1 -
1 -
1 -
74
1 .
kJ
mol
3
6.0
J
K
mol
310
K
298
.
15
K
73
7 .
kJ
mol
And the entropies for the surroundings and universe:
-1
H
-
dq
7
3.7
kJ
mol
ΔS
reaction
1 -
1
237
7 .
J
mol
K
surroundin
gs
T
T
310
K
ΔS
ΔS
ΔS
-1
-1
-1
1
-1
1
176.4
J
K
mol
237
7 .
J
mol
K
414
.
J 1
mol
K
universe
reaction
surroundin
gs
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