Chemistry Worksheets - Chem 340, Fall 2013 Page 11
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19P5.20) Consider the formation of glucose from carbon dioxide and water, that is, the
O(l) C
reaction of the following photosynthetic process: 6CO
(g) + 6H
H
O
(s) +
2
2
6
12
6
6O
(g). The following table of information will be useful in working this problem:
2
T = 298 K
CO
(g)
H
O (l)
C
H
O
(s)
O
(g)
2
2
6
12
6
2
–393.5
–285.8
–1273.1
1
0.0
H
kJ mol
f
–1
–1
S° J mol
K
213.8
70.0
209.2
205.2
37.1
75.3
219.2
29.4
1
1
C
J mol
K
P,m
Calculate the entropy and enthalpy changes for this chemical system at T = 298 K and
T = 330. K. Calculate also the entropy of the surrounding and the universe at both
temperatures.
The standard entropy and enthalpy and heat capacity for this reaction are:
ΔS
ν
(
298
K
)
S
reaction
i
i f,
i
1 -
1
1 -
1
1
2
09.2
J
K
mol
6
2
05.2
J
K
mol
1 -
1
1 -
1
1 -
1 -
6
7
0.0
J
K
mol
6
2
13.8
J
K
mol
262
4 .
J
K
mol
ΔH
ν
(
298
K
)
H
reaction
i
i f,
i
1
1
1
1273
1 .
kJ
mol
6
0
kJ
mol
1
1
6
285
8 .
kJ
mol
6
393
5 .
kJ
mol
1 -
2802
7 .
kJ
mol
-1
1
-1
1
C
(
298
K
)
1
2
19.2
J
K
mol
6
2
9.4
J
K
mol
p,
reaction
1 -
1
1 -
1
6
7
5.3
J
K
mol
6
3
7.1
J
K
mol
1 -
1 -
278
8 .
J
K
mol
At 310 K the entropy and enthalpy for this reaction are then:
T
ΔS
ΔS
f
(
310
K
)
(
298
K
)
C
ln
reaction
reaction
p,
reaction
T
i
330
K
1 -
1 -
1 -
1 -
1 -
1 -
262
4 .
J
K
mol
278.8
J
K
mol
ln
290
7 .
J
K
mol
298
.
15
K
ΔH
ΔH
(
310
K
)
(
298
K
)
C
T
T
reaction
reaction
reaction
f
i
1 -
1 -
1 -
1 -
2
802.7
kJ
mol
278.8
J
K
mol
330
K
298
.
15
K
2793
8 .
kJ
mol
And the entropies for the surroundings and universe:
-1
2793.8 kJ mol
-dq
H
ΔS
8.47 10 J mol K
3
-1
1
reaction
surroundings
T
T
330 K
ΔS
ΔS
ΔS
290.47 J K mol
8.47 10 J mol K
-1
-1
3
-1
1
universe
reaction
surroundings
3
-1
1
8.76 10 J mol K
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