Chemistry Worksheets - Chem 340, Fall 2013 Page 9

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Engel
–1
–1
P5.14) The standard entropy of Pb(s) at 298.15 K is 64.80 J K
mol
. Assume that
the heat capacity of Pb(s) is given by
 
2
C
Pb,s
T
T
5
P,m
 22.13  0.01172
 1.00  10
1
1
2
K
J mol
K
K
The melting point is 327.4°C and the heat of fusion under these conditions is 4770. J
–1
mol
. Assume that the heat capacity of Pb(l) is given by
C
Pb,l
T
P,m
 32.51  0.00301
1
1
K
J K
mol
a. Calculate the standard entropy of Pb(l) at 500°C.
b.Calculate H for the transformation Pb(s,25°C)  Pb(l,500°C).
a)
600.55 K
ΔH
773.15 K
C
C
p,m
p,m
fusion
S
Pb, ,773 K
S
Pb,s,298.15 K
d T/K
d T/K
m
m
T/K
T
T/K
fusion
298.15 K
600.55 K
 
 
5
2
2
1
600.55 K
22.13
0.01172 T/K
1.00 10
T /K
4770 J mol
d T/K
T/K
600.55 K
298.15 K
 
773.15 K
32.51
0.003
01 T/K
d T/K
T/K
600.55 K
 
 
 
1
1
1
1
1
1
1
1
64.80 J mol K
20.40 J mol K
7.94 J mol K
7.69 J mol K
1
1
100.8 J mol K
b)
600.55
K
773.15
K
ΔH
solid
liquid
H
C
d
T/K
C
d
T/K
total
p,
m
fusion
p,
m
298.15
K
600.55
K
 
 
1
1
1
8918
J
mol
4770
J
mol
5254
J
mol
3
1
1
8.94
10
J
mol

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