Chemistry Worksheet With Answer Key - Chem 10113, Quiz 1b Page 24
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2412. (15 points) SHOW ALL WORK. Given 450.0 g of hot tea at 75.0 °C, what mass of
= 4.184 J/g∙°C and
ice at 0 °C must be added to obtain iced tea at 15.0 °C? For tea, C
s
H
for ice is 6.01 kJ/mol. [note; to simplify, ignore the contribution of the melted ice
fus
warming to 15 °C.]
q=m C
T
s
q=(450.0 g)(4.184 J/g C)(60.0 C) = 122968 J needed
122968 J x mol
= 20.46 mol ice x 18.015 g/mol = 339 g
6010 J
24
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