Chemistry Worksheet With Answer Key - Chem 10113, Quiz 1b Page 8
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24yes liquid will be present
12. (15 points) SHOW ALL WORK. Given 400.0 g of hot tea at 80.0 °C, what mass of
= 4.184 J/g∙°C and
ice at 0 °C must be added to obtain iced tea at 10.0 °C? For tea, C
s
H
for ice is 6.01 kJ/mol. [note; to simplify, ignore the contribution of the melted ice
fus
warming to 10 °C.]
q=m C
T
s
q=(400.0 g)(4.184 J/g C)(70.0 C) = 117152 J needed
117152 J x 1 mol
= 19.49 mol ice x 18.015 g/mol = 351 g
6010 J
8
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