Sample Design Calculations Page 31
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37C
SAMPLE DESIGN CALCULATIONS
APPENDIX
Wet Floodproofing
EXAMPLE C7. NET BUOYANCY FORCE ON A LIQUID PROPANE TANK
Given:
• F
= the net buoyancy force of the tank, in lbs
b
• V
= the volume of the tank in gallons = 250 gal
t
• 0.134 is a factor to convert gal to ft
3
• = the specific weight of flood water surrounding the tank (generally 62.4 lb/ft
3
for fresh
water and 64.1 lb/ft
3
for salt water)
• FS = the factor of safety to be applied to the computation, typically 1.3 for tanks
• W
= the weight of the tank = 670 lbs (empty – worst case scenario)
t
• V
= the volume of concrete required, in ft
3
c
• S
= the effective weight of concrete, typically 150 lb/ft
3
c
Find:
1. The net buoyancy force of the tank in pounds
2. The volume of concrete required to offset the buoyant force
Solution for #1: The net buoyancy force of the liquid propane tank can be found as follows:
=
2,048 lb
Solution for #2: The volume of concrete required to offset the buoyant force can be determined as
follows:
Where:
V
=
23.4 ft
3
c
C-31
ENGINEERING PRINCIPLES AND PRACTICES for Retrofitting Flood-Prone Residential Structures
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