Ibps So Marketing Exam Template With Answers Page 37
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48IBPS SO Marketing Set
Thus, we have to arrange the letters SFTWR (OAE).
Now, 5 letters can be arranged in 6! = 720 ways
The vowels (OAE) can be arranged among themselves in 3! = 6 ways.
Required number of ways = (720 × 6) = 4320
42.
Option D
The word AUCTION has 7 different letters.
When the vowels AUIO are always together, they can be supposed to form one letter.
Then,we have to arrange the letters CTN (AUIO).
Now, 4 letters can be arranged in 4! = 24 ways.
The vowels (AUIO) can be arranged among themselves in 4! = 24 ways.
Required number of ways = (24 × 24) = 576
43.
Option B
In order that two books on Hindi are never together, we must place all these books as under:
X E X E X E X …. X E X
Where E denotes the position of an English book and X that of a Hindi book.
×
×
Since there are 21 books on English, the number of places marked X are therefore, 22
×
×
Now, 19 places out of 22 can be chosen in 22C19 = 22C3 =
= 1540 ways
Hence, the required number of ways = 1540
44.
Option B
Since a - b is divisible by 3 if either a and b are divisible by 3 or none of a and b is divisible
Out of 30 numbers 2 numbers can be chosen in 30C2 ways.
So, exhaustive number of cases = 30C2 = 435
by 3. Thus, the favourable numbers, of cases = 10C2 + 20C2 = 235
Hence, required probability =
=
45.
Option C
Required probability =
×
=
46.
Option C
Let x% is second discount, then 45 × 450 × 90/100 × (100 – x/100) = 344.25
= 405 (100 - x/100) = 344.25 = 100 – x = 85
x = 15
47.
Option D
CP of 60 connections = 54 / 10 × 60 = 324
SP = 38/6 × 60 = 380
For gain of (380 – 324) = 56, no. of connections = 60 for 1120, connections = 60 × 20 = 1200
48.
Option C
5x + 2 × (2x) = 120 × 3 → 40
2x = 80
49.
Option B
0.95x + 1.15y = (x + y) + 7
1.05x + 1.1y = (x + y) + 13
y = 80
x = CP of Pen
y = CP of book
50.
Option C
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Page 37
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