Oxidation-Reduction Reactions Chemistry Worksheet Page 36

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242
Chapter 6
Oxidation-Reduction Reactions
71.
Mn
(PO
)
, which is used to make corrosion resistant coatings on steel,
3
4
2
aluminum, and other metals, is made from the reaction of Mn(OH)
with
2
H
PO
.
3
4
(s) + 2H
(aq) → Mn
(s) + 6H
3Mn(OH)
PO
(PO
)
O(l )
2
3
4
3
4
2
2
Determine the oxidation number for each atom in the equation and identify
whether the reaction is a redox reaction or not. If it is redox, identify what is
oxidized, what is reduced, the oxidizing agent, and the reducing agent.
72. One of the ways that plants generate oxygen is represented by the following
reaction.
+
4+
2+
+ 2H
O → 2Mn
+ 4H
+ O
2Mn
2
2
Determine the oxidation number for each atom in the equation and decide
whether the reaction is a redox reaction or not. If it is redox, identify which
substance is oxidized, which substance is reduced, the oxidizing agent, and the
reducing agent.
73.
The noble gases in group 18 on the periodic table used to be called the inert gases
because they were thought to be incapable of forming compounds. Their name
has been changed to noble gases because although they resist combining with
the more common elements to their left on the periodic table, they do mingle
with them on rare occasions. The following equations describe reactions that
form xenon compounds. Determine the oxidation number for each atom in the
reactions, and identify each reaction as redox or not. If it is redox, identify which
substance is oxidized, which substance is reduced, the oxidizing agent, and the
reducing agent.
Xe + 3F
→ XeF
2
6
+ H
O → XeOF
+ 2HF
XeF
6
2
4
+ OPF
→ XeOF
+ PF
XeF
6
3
4
5
74. Sometimes one of the elements in a reactant appears in more than one product
of a reaction and has in one product, a higher oxidation number than before
the reaction and in the other product, a lower oxidation number than before
the reaction. In this way, the same element is both oxidized and reduced, and
the same compound is both the oxidizing agent and the reducing agent. This
process is called disproportionation. For example, iodine monofluoride, IF,
disproportionates into iodine and iodine pentafluoride in the following reaction:
5IF → 2I
+ IF
2
5
Determine the oxidation number for each atom in this equation and show that
iodine is both oxidized and reduced and that iodine monofluoride is both the
oxidizing agent and the reducing agent.

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