Chem 161 Chapter 9 Molecular Geometry Worksheet - Shape Determines Function Page 17
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40P orbitals are dumbbell-shaped, so two 2p orbitals for the two F atoms in F
bond by having an
2
overlapping region where the two electrons are shared.
Case #1: BeH
2
1. Draw the Lewis formula for the BeH
molecule below:
2
Lewis formula
Sketch of molecule
2. The BeH
molecule’s shape is ____________ and the bond angle is ________.
2
Sketch the molecule in the space provided above.
3. The electron configuration for Be: ____________
4. The ground state orbital diagram for Be should be as follows:
.
2p
↑↓
2s
– BUT this indicates that Be does not form covalent bonds with H since Be's
electrons are already paired.
for Be to make two bonds, one of Be's 2s electrons must be promoted
→
to the 2p orbital:
.
↑
2p
↑
2s
– Now there are two unpaired electrons available to bond to each H, but this orbital diagram
indicates that the two Be–H bonds are different since one forms with a 2s orbital and other
from a 2p orbital.
– BUT VSEPR predicts BeH
is linear and experiment indicates that the two
2
Be–H bonds are equivalent
inconsistency between VSEPR and orbitals
→
How do you get two equivalent atomic orbitals that are oriented 180° from each other when s
orbitals are spherical and p orbitals are dumbbell shaped?
Hybridize the atomic orbitals!
→
CHEM
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C hapter
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