Chem 161 Chapter 9 Molecular Geometry Worksheet - Shape Determines Function Page 28
ADVERTISEMENT
1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27
28
29
30
31
32
33
34
35
36
37
38
39
409.5 SHAPES AND BONDING IN LARGER MOLECULES
Double Bond Case: ethylene, C
H
:
2
4
1. Draw the Lewis structure for C
H
using the skeletal structure below:
2
4
H
H
C
C
H
H
2. The shape around each C is ____________________, and the bond angle is _________.
3. Electron configuration for C (using core notation): ___________________
4. Draw the atomic orbital diagram
for the valence electrons in C, promoting
electrons in the atomic orbital diagram,
so C can form 4 bonds.
5. Given the shape around each C atom, C has _______ atomic hybrid orbitals.
6. Show the atomic orbital diagrams forming the three hybrid orbitals for each C atom below:
hybridization
"
" " " " "
→
atomic orbital diagram before hybridizing
atomic orbital diagram after hybridizing
€
sigma (σ) bonds:
– covalent bond formed by directly overlapping orbitals
– for example, all of the bonds we’ve seen between the hybrid orbitals on the central atom
and the outer atoms’ orbitals have all been sigma bonds
– The electron density is concentrated between the two nuclei of bonding atoms.
– single bonds are generally sigma bonds
– only the first bond in double and triple bonds can be a sigma bond
pi (π) bond: (usually second and third bonds in double and triple bonds)
– covalent bond formed by sideways interaction between adjacent orbitals
– electron density concentrated above and below plane of the nuclei of bonding atoms
Example: Indicate the sigma and pi bonds in the ethylene molecule below:
H
H
_____ σ bonds
C
C
H
H
_____ π bonds
CHEM
1 61:
C hapter
9
page
2 8
o f
4 0
ADVERTISEMENT
0 votes
Related Articles
Related forms
Related Categories
Parent category: Education